The energy levels of the hydrogen spectrum are shown in the figure. There are some transitions $A, B, C, D$ and $E$. Transitions $A, B$ and $C$ respectively represent:

  • A
    First member of Lyman series,third spectral line of Balmer series and the second spectral line of Paschen series
  • B
    Ionization potential of hydrogen,second spectral line of Balmer series and third spectral line of Paschen series
  • C
    Series limit of Lyman series,third spectral line of Balmer series and second spectral line of Paschen series
  • D
    Series limit of Lyman series,second spectral line of Balmer series and third spectral line of Paschen series

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Similar Questions

The shortest wavelength in the Balmer series of the hydrogen atom spectrum is approximately equal to (use $R_{H} = 1.097 \times 10^7 \ \text{m}^{-1}$) (in $\text{Å}$)

In terms of Rydberg constant $R,$ the shortest wavelength in the Balmer series of the Hydrogen atom spectrum will be:

Find the ratio of the first wavelengths of the Lyman series and the Balmer series.

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Ratio of longest wavelength corresponding to Lyman and Balmer series in hydrogen spectrum is

For the wavelength of visible radiation of the hydrogen spectrum,Balmer gave an equation as $\lambda = \frac{(k m^2)}{(m^2 - 4)}$,where $m$ is an integer. The value of $k$ in terms of Rydberg's constant $R$ is

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