The energy of one mole of photons of radiatio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy of one photon is given by $E = h
u$. The energy of one mole of photons is given by $E = N_A 	imes h 	imes 
u$. Substituting the giv

Vedclass · Accepted Answer

$798$

Vedclass · Answer

(B) The energy of one photon is given by $E = h
u$. The energy of one mole of photons is given by $E = N_A 	imes h 	imes 
u$. Substituting the given values: $E = (6.022 	imes 10^{23} \ mol^{-1}) 	imes (6.626 	imes 10^{-34} \ Js) 	imes (2 	imes 10^{12} \ s^{-1})$. $E = 6.022 	imes 6.626 	imes 2 	imes 10^{23-34+12} \ J \ mol^{-1}$. $E = 79.795 	imes 10^{1} \ J \ mol^{-1} = 797.95 \ J \ mol^{-1}$. Rounding to the nearest integer,we get $798 \ J \ mol^{-1}$.

The energy of one mole of photons of radiation of frequency $2 \times 10^{12} \ Hz$ in $J \ mol^{-1}$ is $.....$ (Nearest integer) (Given: $h = 6.626 \times 10^{-34} \ Js$,$N_A = 6.022 \times 10^{23} \ mol^{-1}$)

Similar Questions

In the hydrogen spectrum,the various lines of the Lyman series lie in the $.......$ region.

The wavelength of blue light is $480 \ nm$. What is the frequency of this light?

Calculate the frequency in $Hz$ of orange colour light having wavelength $600 \ nm$. $[c = 3 \times 10^8 \ ms^{-1}]$

The wavelength of sodium light is $5.862 \times 10^{-16} \, m$. The energy of the photon will be .....

The energy of a radiation of wavelength $8000 \ \mathring{A}$ is $E_1$ and energy of a radiation of wavelength $16000 \ \mathring{A}$ is $E_2$. What is the relation between these two?

Vedclass Test Series

Exam Paper Generator

Online Exam Module