The energy of the third orbit of Li^{2+} ion | vedclass

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Question

(A) The energy of an electron in the $n^{th}$ orbit of a hydrogen-like species is given by the formula: $E_n = -2.18 	imes 10^{-18} 	imes \frac{Z^2}

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$-2.18 	imes 10^{-18}$

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(A) The energy of an electron in the $n^{th}$ orbit of a hydrogen-like species is given by the formula: $E_n = -2.18 	imes 10^{-18} 	imes \frac{Z^2}{n^2} \ J$. For $Li^{2+}$ ion,the atomic number $Z = 3$. For the third orbit,$n = 3$. Substituting these values into the formula: $E_3 = -2.18 	imes 10^{-18} 	imes \frac{3^2}{3^2} \ J$. $E_3 = -2.18 	imes 10^{-18} 	imes \frac{9}{9} \ J$. $E_3 = -2.18 	imes 10^{-18} \ J$.

The energy of the third orbit of $Li^{2+}$ ion (in $J$) is

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