(A) Given,the inductance $L = 50 mH = 50 \times 10^{-3} H = 5 \times 10^{-2} H$.The current $I = 4 A$.The energy $E$ stored in an inductor is given by

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(A) Given,the inductance $L = 50 mH = 50 \times 10^{-3} H = 5 \times 10^{-2} H$.The current $I = 4 A$.The energy $E$ stored in an inductor is given by the formula $E = \frac{1}{2} L I^2$.Substituting the values,we get $E = \frac{1}{2} \times (5 \times 10^{-2}) \times (4)^2$.$E = \frac{1}{2} \times 5 \times 10^{-2} \times 16$.$E = 5 \times 10^{-2} \times 8 = 40 \times 10^{-2} J = 0.4 J$.

Class 12 Physics Electromagnetic Induction Energy Stored in Inductor

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The energy stored in a $50 mH$ inductor carrying a current of $4 A$ is (in $J$)

AP EAMCET 2020 All AP EAMCET

A
$0.4$
B
$4.0$
C
$0.8$
D
$0.04$

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The energy stored in a $50 mH$ inductor carrying a current of $4 A$ is (in $J$)

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