The enthalpy of combustion of propane,graphit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formation reaction for propane is: $3C_{(gr)} + 4H_{2(g)} \rightarrow C_{3}H_{8(g)}$The enthalpy of formation $\Delta H_f$ is calculated using

Vedclass · Accepted Answer

$104$

Vedclass · Answer

(C) The formation reaction for propane is: $3C_{(gr)} + 4H_{2(g)} ightarrow C_{3}H_{8(g)}$The enthalpy of formation $\Delta H_f$ is calculated using the formula: $\Delta H_f = \sum \Delta H_{c}(	ext{reactants}) - \sum \Delta H_{c}(	ext{products})$$\Delta H_f = [3 	imes \Delta H_{c}(C) + 4 	imes \Delta H_{c}(H_{2})] - \Delta H_{c}(C_{3}H_{8})$$\Delta H_f = [3(-393.5) + 4(-285.8)] - (-2220.0)$$\Delta H_f = [-1180.5 - 1143.2] + 2220.0$$\Delta H_f = -2323.7 + 2220.0 = -103.7 \ kJ \ mol^{-1}$The magnitude of the enthalpy of formation is $|-103.7| = 103.7 \ kJ \ mol^{-1}$.Rounding to the nearest integer,we get $104 \ kJ \ mol^{-1}$.

The enthalpy of combustion of propane,graphite and dihydrogen at $298 \ K$ are: $-2220.0 \ kJ \ mol^{-1}$,$-393.5 \ kJ \ mol^{-1}$ and $-285.8 \ kJ \ mol^{-1}$ respectively. The magnitude of the enthalpy of formation of propane $(C_{3}H_{8})$ is ......... $kJ \ mol^{-1}$. (Nearest integer)

Similar Questions

The standard heats of formation in $kcal \ mol^{-1}$ of $NO_{2(g)}$ and $N_2O_{4(g)}$ are $8.0$ and $2.0$ respectively. The heat of dimerization of $NO_2$ in $kcal$ for the reaction $2NO_{2(g)} \rightarrow N_2O_{4(g)}$ is:

Given
$N_{2(g)} + 3H_{2(g)} \longrightarrow 2NH_{3(g)} \quad \Delta_{r}H^{\theta} = -92.4 \, kJ \, mol^{-1}$
What is the standard enthalpy of formation of $NH_{3}$ gas?

The enthalpy change for a reaction does not depend on:

Given:
$C + 2S \to CS_2 ; \Delta H_f^o = +117.0 \, kJ \, mol^{-1} \dots (1)$
$C + O_2 \to CO_2 ; \Delta H_f^o = -393 \, kJ \, mol^{-1} \dots (2)$
$S + O_2 \to SO_2 ; \Delta H_f^o = -297 \, kJ \, mol^{-1} \dots (3)$
The heat of reaction for $CS_2 + 3O_2 \to CO_2 + 2SO_2$ is:
.....$kJ \, mol^{-1}$

What amount of energy (in $KJ$) is released in the combustion of $5.8\, g$ of $C_4H_{10}\,(g)$?
$2 C_4H_{10}(g) + 13 O_2(g) \to 8 CO_2(g) + 10 H_2O(l)$; $\Delta H^o = -5756\, KJ$

Vedclass Test Series

Exam Paper Generator

Online Exam Module