The entropy values (in $J \, K^{-1} \, mol^{-1}$) of $H_{2(g)} = 130.6$,$Cl_{2(g)} = 223.0$,and $HCl_{(g)} = 186.7$ at $298 \, K$ and $1 \, atm$ pressure. Then entropy change for the reaction $H_{2(g)} + Cl_{2(g)} \to 2HCl_{(g)}$ is
- A$540.3$
- B$727.3$
- C$-166.9$
- D$19.8$
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