The equation $\Delta x \cdot \Delta p \ge \frac{h}{4\pi}$ shows

Calculate the mass of an elementary particle,which is accelerated to twice the velocity of light with the precision $\pm 1 \%$,and has $1.05 \times 10^{-13} \ m$ uncertainty in position. $(h = 6.6 \times 10^{-34} \ kg \ m^2 \ s^{-1})$

Assertion : It is impossible to determine the exact position and exact momentum of an electron simultaneously.
Reason : The path of an electron in an atom is clearly defined.

What is the value of $\Delta v \cdot \Delta x$ for an electron? What does it indicate?

The uncertainty in position is $10^{-10} \ m$ and in velocity is $5.27 \times 10^{-24} \ m \ s^{-1}$. Calculate the mass of the particle.

Given: The mass of an electron is $9.1 \times 10^{-31} \ kg$,Planck's constant is $6.62 \times 10^{-34} \ J \cdot s$. The uncertainty involved in the measurement of velocity within a distance of $0.1 \ \mathring{A}$ is: