The equation of a curve is given as y = x^2 - | vedclass

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(C) To find the points where the curve intersects the $x$-axis,we set $y = 0$.Given the equation: $x^2 - 3x + 2 = 0$.Factoring the quadratic equation:

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Both $(1, 0)$ and $(2, 0)$

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(C) To find the points where the curve intersects the $x$-axis,we set $y = 0$.Given the equation: $x^2 - 3x + 2 = 0$.Factoring the quadratic equation: $x^2 - 2x - x + 2 = 0$.$x(x - 2) - 1(x - 2) = 0$.$(x - 1)(x - 2) = 0$.This gives the roots $x = 1$ and $x = 2$.Therefore,the curve intersects the $x$-axis at the points $(1, 0)$ and $(2, 0)$.

The equation of a curve is given as $y = x^2 - 3x + 2$. The curve intersects the $x$-axis at

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