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(B) The standard equation of a wave is given by $y = a \cos (\omega t - kx)$.Given equation: $y = 20 \cos (50\pi t - \pi x)$.Comparing the given equat

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$2$

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(B) The standard equation of a wave is given by $y = a \cos (\omega t - kx)$.Given equation: $y = 20 \cos (50\pi t - \pi x)$.Comparing the given equation with the standard equation,we get the wave number $k = \pi$.We know that the wave number $k$ is related to the wavelength $\lambda$ by the formula $k = \frac{2\pi}{\lambda}$.Substituting the value of $k$: $\pi = \frac{2\pi}{\lambda}$.Solving for $\lambda$: $\lambda = \frac{2\pi}{\pi} = 2 \, cm$.

The equation of a longitudinal wave is represented as $y = 20 \cos \pi (50t - x)$. Its wavelength is ..... $cm$.

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