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(A) The standard equation of a plane progressive wave is given by $y = a \sin (\omega t + kx)$.Comparing the given equation $y = 0.025 \sin (100t + 0.

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$\frac{50}{\pi} 	ext{ Hz}$

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(A) The standard equation of a plane progressive wave is given by $y = a \sin (\omega t + kx)$.Comparing the given equation $y = 0.025 \sin (100t + 0.25x)$ with the standard equation,we identify the angular frequency $\omega = 100 	ext{ rad/s}$.We know that the relationship between angular frequency $\omega$ and frequency $n$ is given by $\omega = 2\pi n$.Substituting the value of $\omega$,we get $100 = 2\pi n$.Solving for $n$,we find $n = \frac{100}{2\pi} = \frac{50}{\pi} 	ext{ Hz}$.

The equation of a plane progressive wave is given by $y = 0.025 \sin (100t + 0.25x)$. The frequency of this wave would be

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