The equation of a simple harmonic wave is given as $y = 5 \sin \frac{\pi}{2}(100t - x)$,where $x$ and $y$ are in meters and time $t$ is in seconds. The period of the wave is: (in $s$)

The rope shown at an instant is carrying a wave travelling towards the right,created by a source vibrating at a frequency $n$. Consider the following statements:
$I.$ The speed of the wave is $4n \times ab$
$II.$ The medium at $a$ will be in the same phase as $d$ after $\frac{4}{3n} \text{ s}$
$III.$ The phase difference between $b$ and $e$ is $\frac{3\pi}{2}$
Which of these statements are correct?

$A$ travelling harmonic wave on a string is described by $y(x, t) = 7.5 \sin (0.0050 x + 12 t + \pi / 4)$.
$(a)$ What are the displacement and velocity of oscillation of a point at $x = 1 \; cm$ and $t = 1 \; s$? Is this velocity equal to the velocity of wave propagation?
$(b)$ Locate the points of the string which have the same transverse displacements and velocity as the $x = 1 \; cm$ point at $t = 2 \; s, 5 \; s$ and $11 \; s$.

$A$ plane wave $y = A \sin \omega \left( t - \frac{x}{v} \right)$ undergoes normal incidence on a plane boundary separating medium $M_1$ and $M_2$ and splits into a reflected and transmitted wave having speeds $v_1$ and $v_2$. Then:

The equation of a transverse wave is given by $y = 100 \sin \pi (0.04z - 2t)$,where $y$ and $z$ are in $cm$ and $t$ is in seconds. The frequency of the wave in $Hz$ is

$A$ transverse wave of amplitude $0.5\, m$,wavelength $1\, m$,and frequency $2\, Hz$ is propagating in a string in the negative $x$-direction. The expression for this wave is: