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(B) Given equation is $3x^2 - 20x + 17 = 0$.To find the equation whose roots are the reciprocals of the roots of $ax^2 + bx + c = 0$,we replace $x$ wi

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$17x^2 - 20x + 3 = 0$

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(B) Given equation is $3x^2 - 20x + 17 = 0$.To find the equation whose roots are the reciprocals of the roots of $ax^2 + bx + c = 0$,we replace $x$ with $\frac{1}{x}$.Substituting $\frac{1}{x}$ in the given equation:$3(\frac{1}{x})^2 - 20(\frac{1}{x}) + 17 = 0$$\frac{3}{x^2} - \frac{20}{x} + 17 = 0$Multiplying the entire equation by $x^2$:$3 - 20x + 17x^2 = 0$Rearranging the terms,we get $17x^2 - 20x + 3 = 0$.

The equation whose roots are reciprocal of the roots of the equation $3x^2 - 20x + 17 = 0$ is

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