The equilibrium constant for the reversible reaction,$N_2 + 3H_2 \rightleftharpoons 2NH_3$ is $K$ and for the reaction $\frac{1}{2}N_2 + \frac{3}{2}H_2 \rightleftharpoons NH_3$ the equilibrium constant is $K'$. $K$ and $K'$ will be related as
- A$K = K'$
- B$K' = \sqrt{K}$
- C$K = \sqrt{K'}$
- D$K \times K' = 1$
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Match List-$I$ (Hypothetical reaction) with List-$II$ (Ratio of $K_p/K_c$ for the given reaction) and select the correct answer using the options given below.
$(1)$ $A_{2(g)} + 3B_{2(g)} \rightleftharpoons 2AB_{3(g)}$ $(i)$ $(RT)^{-2}$ $(2)$ $A_{2(g)} + B_{2(g)} \rightleftharpoons 2AB_{(g)}$ $(ii)$ $(RT)^0$ $(3)$ $A_{(s)} + 1.5B_{2(g)} \rightleftharpoons AB_{3(g)}$ $(iii)$ $(RT)^{1/2}$ $(4)$ $AB_{2(g)} \rightleftharpoons AB_{(g)} + 0.5B_{2(g)}$ $(iv)$ $(RT)^{-1/2}$
| $(1)$ $A_{2(g)} + 3B_{2(g)} \rightleftharpoons 2AB_{3(g)}$ | $(i)$ $(RT)^{-2}$ |
| $(2)$ $A_{2(g)} + B_{2(g)} \rightleftharpoons 2AB_{(g)}$ | $(ii)$ $(RT)^0$ |
| $(3)$ $A_{(s)} + 1.5B_{2(g)} \rightleftharpoons AB_{3(g)}$ | $(iii)$ $(RT)^{1/2}$ |
| $(4)$ $AB_{2(g)} \rightleftharpoons AB_{(g)} + 0.5B_{2(g)}$ | $(iv)$ $(RT)^{-1/2}$ |
Medium
View SolutionIn which of the following reactions is ${K_p} > {K_c}$?
Medium
View SolutionThe ratio $\frac{K_p}{K_C}$ for the reaction: $CO_{(g)} + \frac{1}{2} O_{2(g)} \rightleftharpoons CO_{2(g)}$ is:
For the reaction $PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$,what is the relationship between $K_p$ and $K_c$?
Medium
View SolutionFor the reaction $2NO_{2(g)} \rightleftharpoons 2NO_{(g)} + O_{2(g)}$,the value of $K_c$ is $1.8 \times 10^{-6}$ at $184^{\circ}C$. Given $R = 0.083 \ L \cdot bar \cdot K^{-1} \cdot mol^{-1}$,compare $K_p$ and $K_c$ at $184^{\circ}C$.
Easy
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