The equivalent conductance of a monobasic aci | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Equivalent conductivity at infinite dilution $\Lambda^{\circ}_{eq} = 348 \, \Omega^{-1} \, cm^2 \, eq^{-1}$.Normality $(N)$ of the solution $= \fr

Vedclass · Accepted Answer

$51.7$

Vedclass · Answer

(D) Equivalent conductivity at infinite dilution $\Lambda^{\circ}_{eq} = 348 \, \Omega^{-1} \, cm^2 \, eq^{-1}$.Normality $(N)$ of the solution $= \frac{	ext{mass}}{	ext{equivalent mass} 	imes 	ext{volume in } L} = \frac{15}{49 	imes 1} \approx 0.3061 \, N$.Conductivity $(\kappa) = \frac{1}{	ext{resistivity}} = \frac{1}{18.5} \approx 0.05405 \, \Omega^{-1} \, cm^{-1}$.Equivalent conductivity $(\Lambda_{eq}) = \frac{\kappa 	imes 1000}{N} = \frac{0.05405 	imes 1000}{0.3061} \approx 176.58 \, \Omega^{-1} \, cm^2 \, eq^{-1}$.Degree of dissociation $(\alpha) = \frac{\Lambda_{eq}}{\Lambda^{\circ}_{eq}} = \frac{176.58}{348} \approx 0.5074$.Percentage dissociation $= 0.5074 	imes 100 \approx 50.74 \, \%$,which is closest to $51.7 \, \%$.

Similar Questions

The molar conductivity of a $0.02 \ M$ solution of an electrolyte is $124 \times 10^{-4} \ S \ m^2 \ mol^{-1}$. What is the resistance of the same solution (in ohms),kept in a cell with a cell constant of $129 \ m^{-1}$?

If the resistivity of a $0.8 \ M \ KCl$ solution is $2.5 \times 10^{-3} \ \Omega \ cm$,calculate the molar conductivity of the solution.

Electrical conductance through metals is called metallic or electronic conductance and is due to the movement of electrons. The electronic conductance depends on

Which of the following $M$ solutions of $KCl$ has the lowest value of specific conductivity?

What is the molar conductivity of $0.02 \text{ M}$ $KI$ solution if its conductivity is $4.37 \times 10^{-4} \text{ } \Omega^{-1} \text{cm}^{-1}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module