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(C) Let the nodes be labeled. The circuit consists of five resistors,each of $10 \ \Omega$.By analyzing the circuit,we can see it is a bridge circuit.

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(C) Let the nodes be labeled. The circuit consists of five resistors,each of $10 \ \Omega$.By analyzing the circuit,we can see it is a bridge circuit. Let the nodes be $x$,$A$,$B$,and $y$.The top $10 \ \Omega$ resistor is between $x$ and $A$.The first bottom $10 \ \Omega$ resistor is between $x$ and $A$.These two are in parallel,so their equivalent resistance is $R_1 = \frac{10 	imes 10}{10 + 10} = 5 \ \Omega$.The middle $10 \ \Omega$ resistor is between $A$ and $B$.The last two $10 \ \Omega$ resistors are in parallel between $B$ and $y$,so their equivalent resistance is $R_2 = \frac{10 	imes 10}{10 + 10} = 5 \ \Omega$.Now,the circuit simplifies to three resistors in series: $R_1$,the middle $10 \ \Omega$ resistor,and $R_2$.Total equivalent resistance $R_{eq} = 5 \ \Omega + 10 \ \Omega + 5 \ \Omega = 20 \ \Omega$.

The equivalent resistance between $x$ and $y$ in the circuit shown is ............. $\Omega$

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