The equivalent weight of a metal is 4.5 and t | vedclass

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(B) Let the metal be $M$ and its valency be $x$. The formula of the metal chloride is $MCl_x$.The molecular weight of $MCl_x$ is given by: $	ext{Atom

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$9$

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(B) Let the metal be $M$ and its valency be $x$. The formula of the metal chloride is $MCl_x$.The molecular weight of $MCl_x$ is given by: $	ext{Atomic weight of } M + x 	imes 	ext{Atomic weight of } Cl = 80$.We know that $	ext{Atomic weight of } M = 	ext{Equivalent weight} 	imes 	ext{Valency} = 4.5x$.Substituting this into the molecular weight equation:$4.5x + x(35.5) = 80$$4.5x + 35.5x = 80$$40x = 80$$x = 2$Therefore,the atomic weight of the metal is $4.5 	imes 2 = 9$.

Isotope	Isotopic molar mass $(g \, mol^{-1})$	Abundance (%)
$^{36}Ar$	$35.96755$	$0.337$
$^{38}Ar$	$37.96272$	$0.063$
$^{40}Ar$	$39.9624$	$99.600$

The equivalent weight of a metal is $4.5$ and the molecular weight of its chloride is $80$. The atomic weight of the metal is

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