The equivalent weight of an element is 4. Its | vedclass

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(B) The formula for the molecular weight of a chloride is $M = 2 	imes V.D = 2 	imes 59.25 = 118.5$.Let the valency of the element be $n$ and its eq

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$3$

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(B) The formula for the molecular weight of a chloride is $M = 2 	imes V.D = 2 	imes 59.25 = 118.5$.Let the valency of the element be $n$ and its equivalent weight be $E = 4$.The molecular weight of the chloride $(MCl_n)$ is given by $M = E 	imes n + 35.5 	imes n$.Substituting the values: $118.5 = 4n + 35.5n$.$118.5 = 39.5n$.$n = \frac{118.5}{39.5} = 3$.Therefore,the valency of the element is $3$.

The equivalent weight of an element is $4$. Its chloride has a $V.D$ of $59.25$. Then the valency of the element is:

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