(A) Given that,$P(A) = 0.25$,$P(B) = 0.50$ $P(A \cap B) = 0.14$ Using the addition theorem of probability: $P(A \cup B) = P(A) + P(B) - P(A \cap B)$ $

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(A) Given that,$P(A) = 0.25$,$P(B) = 0.50$ $P(A \cap B) = 0.14$ Using the addition theorem of probability: $P(A \cup B) = P(A) + P(B) - P(A \cap B)$ $P(A \cup B) = 0.25 + 0.50 - 0.14 = 0.61$ The probability that neither $A$ nor $B$ occurs is given by $P(\bar{A} \cap \bar{B})$: $P(\bar{A} \cap \bar{B}) = P(\overline{A \cup B}) = 1 - P(A \cup B)$ $P(\bar{A} \cap \bar{B}) = 1 - 0.61 = 0.39$

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

The events $A$ and $B$ have probabilities $0.25$ and $0.50$,respectively. The probability that both $A$ and $B$ occur simultaneously is $0.14$. Then,the probability that neither $A$ nor $B$ occurs is:

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A
$0.39$
B
$0.29$
C
$0.11$
D
$0.25$

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The events $A$ and $B$ have probabilities $0.25$ and $0.50$,respectively. The probability that both $A$ and $B$ occur simultaneously is $0.14$. Then,the probability that neither $A$ nor $B$ occurs is:

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