The exact volumes of 1, M, NaOH solution requ | vedclass

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(C) $H_3PO_3$ is a dibasic acid ($n$-factor = $2$) and $H_3PO_2$ is a monobasic acid ($n$-factor = $1$).For neutralization,equivalents of base = equiv

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$100\, mL$ and $200\, mL$

Vedclass · Answer

(C) $H_3PO_3$ is a dibasic acid ($n$-factor = $2$) and $H_3PO_2$ is a monobasic acid ($n$-factor = $1$).For neutralization,equivalents of base = equivalents of acid.$(M_1 	imes n_1) 	imes V_1 = (M_2 	imes n_2) 	imes V_2$$1.$ For $H_3PO_3$:$1 	imes 1 	imes V_{NaOH} = 1 	imes 2 	imes 50 \implies V_{NaOH} = 100\, mL$.$2.$ For $H_3PO_2$:$1 	imes 1 	imes V_{NaOH} = 2 	imes 1 	imes 100 \implies V_{NaOH} = 200\, mL$.Therefore,the volumes are $100\, mL$ and $200\, mL$.

The exact volumes of $1\, M\, NaOH$ solution required to neutralize $50\, mL$ of $1\, M\, H_3PO_3$ solution and $100\, mL$ of $2\, M\, H_3PO_2$ solution,respectively,are:

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