The exothermic formation of ClF_3 is represen | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction is exothermic $(\Delta H_r < 0)$. According to Le Chatelier's principle: $1$. Increasing the temperature shifts the equilibrium to th

Vedclass · Accepted Answer

Decreasing the volume of the container

Vedclass · Answer

(D) The reaction is exothermic $(\Delta H_r $1$. Increasing the temperature shifts the equilibrium to the left (reactant side). $2$. Adding an inert gas at constant volume has no effect on the equilibrium position. $3$. Removing $Cl_2$ shifts the equilibrium to the left. $4$. Decreasing the volume of the container increases the pressure,shifting the equilibrium toward the side with fewer moles of gas. In this reaction,there are $4$ moles of gas on the reactant side and $2$ moles on the product side. Thus,decreasing the volume shifts the equilibrium to the right,increasing the yield of $ClF_3$.

The exothermic formation of $ClF_3$ is represented by the equation
$Cl_{2(g)} + 3F_{2(g)} \rightleftharpoons 2ClF_{3(g)}$; $\Delta H_r = -329 \ kJ$
Which of the following will increase the quantity of $ClF_3$ in an equilibrium mixture of $Cl_2, F_2$ and $ClF_3$?

Similar Questions

Sodium sulphate dissolves in water with the evolution of heat. Consider a saturated solution of sodium sulphate. If the temperature is raised,then according to Le Chatelier's principle:

In the production of $NO$,the reaction is $N_2(g) + O_2(g) \rightleftharpoons 2NO(g)$,$\Delta H = +ve$. This reaction is favored by:

When $I_2$ dissociates to its atomic form the following reaction occurs:
$I_{2(g)} \rightleftharpoons 2I_{(g)} ; \Delta_r H^o = +150 \ kJ \ mol^{-1}$
The forward reaction is favoured at:

What happens when a saturated solution of $CO_2$ is heated?

Le Chatelier's principle is applicable to which of the following?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The exothermic formation of $ClF_3$ is represented by the equation$Cl_{2(g)} + 3F_{2(g)} \rightleftharpoons 2ClF_{3(g)}$; $\Delta H_r = -329 \ kJ$Which of the following will increase the quantity of $ClF_3$ in an equilibrium mixture of $Cl_2, F_2$ and $ClF_3$?