The expression for magnetic induction inside a solenoid of length $L$ carrying a current $I$ and having $N$ number of turns is

  • A
    $\frac{\mu_0}{4\pi} \frac{N}{LI}$
  • B
    $\mu_0 NI$
  • C
    $\frac{\mu_0}{4\pi} NLI$
  • D
    $\mu_0 \frac{N}{L} I$

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Similar Questions

The magnetic intensity at the centre of a long current-carrying solenoid is found to be $1.6 \times 10^3 \text{ A m}^{-1}$. If the number of turns is $8 \text{ per cm}$,then the current flowing through the solenoid is $................\, \text{A}$.

The magnetic induction produced inside an ideal solenoid depends on which of the following quantities?
$(a)$ Number of turns per unit length $(n)$.
$(b)$ Radius of the wire.
$(c)$ Current flowing through it $(I)$.
$(d)$ Permeability of the medium $(\mu)$.

Which of the following statements is incorrect for a current-carrying solenoid?

Derive the expression for the magnetic field inside a long straight solenoid.

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View Solution

Inductance per unit length near the middle of a long solenoid is ($\mu_0=$ permeability of free space,$n=$ number of turns per unit length,$d=$ the diameter of the solenoid).

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