The figure shows a portion of a circuit. What | vedclass

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(B) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction equals the sum of currents leaving it.By analyzing the circui

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(B) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction equals the sum of currents leaving it.By analyzing the circuit step-by-step from left to right:$1$. At the first junction,$2 \ A$ and $3 \ A$ enter,so $5 \ A$ leaves towards the next junction.$2$. At the next vertical junction,$5 \ A$ enters from the left and $4 \ A$ enters from below,totaling $9 \ A$. Out of this,$1 \ A$ leaves upwards and $2 \ A$ leaves to the right,so $9 - 1 - 2 = 6 \ A$ must flow downwards to the next junction.$3$. At the final junction on the right,$6 \ A$ enters from the left and $2 \ A$ enters from the right. Therefore,the total current $i$ leaving this junction is $6 \ A + 2 \ A = 8 \ A$ towards the right.

The figure shows a portion of a circuit. What are the magnitude and direction of the current $i$ in the lower right-hand wire (in $A$)?

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