(C) The formula for Young's modulus is $Y = \frac{\text{Stress}}{\text{Strain}} = \frac{F/A}{\Delta l/L} = \frac{F \cdot L}{A \cdot \Delta l}$.Here, t

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(C) The formula for Young's modulus is $Y = \frac{\text{Stress}}{\text{Strain}} = \frac{F/A}{\Delta l/L} = \frac{F \cdot L}{A \cdot \Delta l}$.Here, the force $F$ is equal to the load $W$.From the given graph, we can select a point: $W = 60\text{ N}$ and $\Delta l = 6 \times 10^{-4}\text{ m}$.Given values are: length $L = 1\text{ m}$ and cross-sectional area $A = 10^{-5}\text{ m}^2$.Substituting these values into the formula:$Y = \frac{60 \times 1}{10^{-5} \times 6 \times 10^{-4}}$$Y = \frac{60}{6 \times 10^{-9}}$$Y = 10 \times 10^9 = 1.0 \times 10^{10}\text{ N/m}^2$.Therefore, the correct option is $C$.

Class 11 Physics Mechanical Properties of Solids Young’s Modulus

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The figure represents the extension $(\Delta l)$ of a wire of length $1\text{ m}$, suspended from the ceiling of a room at one end with a load $W$ connected to the other end. If the cross-sectional area of the wire is $10^{-5}\text{ m}^2$, then the Young's modulus of the wire is . . . . . . $\text{N/m}^2$.

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A
$1.0 \times 10^{11}$
B
$2.0 \times 10^{10}$
C
$1.0 \times 10^{10}$
D
$2.0 \times 10^{11}$

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Class 11

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Mechanical Properties of Solids

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Young’s Modulus

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Two persons pull a wire towards themselves. Each person exerts a force of $200 \, N$ on the wire. Young's modulus of the material of the wire is $1 \times 10^{11} \, N \, m^{-2}$. The original length of the wire is $2 \, m$ and the area of cross-section is $2 \, cm^2$. The wire will extend in length by $...... \, \mu m$.

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$A$ wire of cross-sectional area $10^{-6} \, m^2$ is elongated by $0.1 \%$ when the tension in it is $1000 \, N$. The Young's modulus of the material of the wire is (Assume radius of the wire is constant).

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If the density of the material increases,the value of Young's modulus

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Two wires of same length having radius of $2 \ mm$ and $1.5 \ mm$ respectively are loaded with same weights. Extension of the second wire is double than that of the first wire. What is the ratio of the Young's modulus of the first wire to that of the second wire?

EasyTS EAMCET 2022

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$A$ truck is pulling a car out of a ditch by means of a steel cable that is $9.1 \, m$ long and has a radius of $5 \, mm$. When the car just begins to move,the tension in the cable is $800 \, N$. How much has the cable stretched? (Young's modulus for steel is $2 \times 10^{11} \, N/m^2$)

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$A$ wire of cross-sectional area $10^{-6} \, m^2$ is elongated by $0.1 \%$ when the tension in it is $1000 \, N$. The Young's modulus of the material of the wire is (Assume radius of the wire is constant).

If the density of the material increases,the value of Young's modulus

Two wires of same length having radius of $2 \ mm$ and $1.5 \ mm$ respectively are loaded with same weights. Extension of the second wire is double than that of the first wire. What is the ratio of the Young's modulus of the first wire to that of the second wire?

$A$ truck is pulling a car out of a ditch by means of a steel cable that is $9.1 \, m$ long and has a radius of $5 \, mm$. When the car just begins to move,the tension in the cable is $800 \, N$. How much has the cable stretched? (Young's modulus for steel is $2 \times 10^{11} \, N/m^2$)

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