The figure represents the instantaneous pictu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The wave is traveling in the negative $x$-direction. To determine the direction of motion of a particle at a given point,we can imagine the wave s

Vedclass · Accepted Answer

both $(A)$ and $(B)$

Vedclass · Answer

(D) The wave is traveling in the negative $x$-direction. To determine the direction of motion of a particle at a given point,we can imagine the wave shifting slightly to the left (negative $x$-direction). Points that are on the 'front' of the wave crest or trough relative to the direction of propagation will move in a specific direction. For a wave moving in the negative $x$-direction: - Points on the rising part of the wave (slope is negative) move upward. - Points on the falling part of the wave (slope is positive) move downward. Looking at the figure: - Point $a$ is on the rising slope of the crest,so it is moving upward. - Point $g$ is on the rising slope of the trough,so it is moving upward. - Point $f$ is at the bottom of the trough,so it is at its extreme position and momentarily at rest. Therefore,both points $a$ and $g$ are moving upward. The correct option is $(D)$.

The figure represents the instantaneous picture of a transverse harmonic wave traveling along the negative $x$-axis. Choose the correct alternative$(s)$ related to the movement of the nine points shown in the figure. The points moving upward is/are

Similar Questions

$A$ body sends a wave $150 \text{ mm}$ long through medium $P$ and $0.30 \text{ m}$ long in medium $Q$. If velocity of the wave in medium $P$ is $80 \text{ cm s}^{-1}$, the velocity of wave in medium $Q$ is (in $\text{ m s}^{-1}$)

The equation of the wave is $Y = 10 \sin \left(\frac{2 \pi t}{30} + \alpha\right)$. If the displacement is $5 \text{ cm}$ at $t = 0$,then the total phase at $t = 7.5 \text{ s}$ will be (Given: $\sin 30^{\circ} = 0.5$)

The equation of a progressive wave is given by $x = 0.05 \cos \left( 4\pi t + \frac{\pi}{4} \right) \, m$. What is the frequency of the wave in $Hz$?

The wave described by $y = 0.25 \sin(10\pi x - 2\pi t)$,where $x$ and $y$ are in $meters$ and $t$ in $seconds$,is a wave travelling along:

The equation of a wave traveling along the $x$-axis is given by $y(x, t) = 0.005 \cos(\alpha x - \beta t)$. If the wavelength and time period of the wave are $0.08 \ m$ and $2.0 \ s$ respectively,find the values of $\alpha$ and $\beta$ in appropriate units.

Vedclass Test Series

Exam Paper Generator

Online Exam Module