(D) The system consists of a man of mass $m$ and a trolley of mass $M$. Since the trolley is placed on a smooth horizontal surface,there is no externa

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(D) The system consists of a man of mass $m$ and a trolley of mass $M$. Since the trolley is placed on a smooth horizontal surface,there is no external horizontal force acting on the system (man $+$ trolley). According to the property of the centre of mass,if the net external force on a system is zero,the acceleration of the centre of mass is zero $(a_{cm} = 0)$. Initially,the system is at rest,so the initial velocity of the centre of mass is zero $(v_{cm} = 0)$. Since the acceleration of the centre of mass is zero and its initial velocity is zero,the centre of mass of the system remains stationary throughout the motion.

Class 11 Physics System of Particles and Rotational Motion Motion of Centre of Mass

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The figure shows a man of mass $m$ standing at the end $A$ of a trolley of mass $M$ placed at rest on a smooth horizontal surface. The man starts moving towards the end $B$ with a velocity $u_{rel}$ with respect to the trolley. The length of the trolley is $L$. As the man walks on the trolley,the centre of mass of the system (man $+$ trolley)

A
accelerates towards left
B
accelerates towards right
C
moves with $u_{rel}$
D
remains stationary

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Class 11 Questions

Class 11

Physics Questions

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System of Particles and Rotational Motion

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Motion of Centre of Mass

$A$ ball of mass $M$ moving with a speed of $2 \ m \ s^{-1}$ hits another ball of mass $1 \ kg$ moving in the same direction with a speed of $1 \ m \ s^{-1}$. If the kinetic energy of the center of mass is $4/3 \ J$,then the magnitude of $M$ is: (in $kg$)

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$A$ boy of mass $20\, kg$ is standing on an $80\, kg$ cart that is free to move. There is negligible friction between the cart and the ground. Initially,the boy is standing $25\, m$ from a wall. If he walks $10\, m$ on the cart towards the wall,then the final distance of the boy from the wall will be ........ $m$

DifficultJEE MAIN 2013

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Two particles have masses $m_1$ and $m_2$. If the first particle $(m_1)$ is moved by a distance $d$ towards the center of mass,by what distance should the second particle $(m_2)$ be moved so that the center of mass of the system remains at the same position?

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Two particles which are initially at rest,move towards each other under the action of their internal attraction. If their speeds are $v$ and $2v$ at any instant,then the speed of centre of mass of the system will be

EasyAIEEE 2002

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Two bodies of masses $m_1$ and $m_2$ are connected by a massless string passing over a massless,frictionless pulley as shown in the figure. Given $m_2 < m_1$. The acceleration of the center of mass of the system is:

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$A$ ball of mass $M$ moving with a speed of $2 \ m \ s^{-1}$ hits another ball of mass $1 \ kg$ moving in the same direction with a speed of $1 \ m \ s^{-1}$. If the kinetic energy of the center of mass is $4/3 \ J$,then the magnitude of $M$ is: (in $kg$)

Two particles have masses $m_1$ and $m_2$. If the first particle $(m_1)$ is moved by a distance $d$ towards the center of mass,by what distance should the second particle $(m_2)$ be moved so that the center of mass of the system remains at the same position?

Two particles which are initially at rest,move towards each other under the action of their internal attraction. If their speeds are $v$ and $2v$ at any instant,then the speed of centre of mass of the system will be

Two bodies of masses $m_1$ and $m_2$ are connected by a massless string passing over a massless,frictionless pulley as shown in the figure. Given $m_2 < m_1$. The acceleration of the center of mass of the system is:

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