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(D) The electric potential $V$ at a distance $r$ from a point charge $q$ is given by $V = \frac{kq}{r}$,where $k = 9 	imes 10^9 	ext{ Nm}^2	ext{C}^

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$\frac{6}{r^2} 	ext{ Vm}^{-1}$

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(D) The electric potential $V$ at a distance $r$ from a point charge $q$ is given by $V = \frac{kq}{r}$,where $k = 9 	imes 10^9 	ext{ Nm}^2	ext{C}^{-2}$.From the figure,for the equipotential surface with potential $V = 60 	ext{ V}$,the radius is $r = 10 	ext{ cm} = 0.1 	ext{ m}$.Substituting these values into the potential formula:$60 = \frac{kq}{0.1}$$kq = 60 	imes 0.1 = 6 	ext{ Vm}$.The magnitude of the electric field $E$ at a distance $r$ from a point charge is given by $E = \frac{kq}{r^2}$.Substituting the value of $kq = 6$ into the electric field formula,we get:$E = \frac{6}{r^2} 	ext{ Vm}^{-1}$.

The figure shows equipotential surfaces concentric at $O$. The magnitude of the electric field at a distance $r$ metres from $O$ is

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