The figure shows the $P-V$ plot of an ideal gas taken through a cycle $ABCDA.$ The part $ABC$ is a semicircle and $CDA$ is half of an ellipse. Then,

  • A
    The process during the path $A \to B$ is isothermal
  • B
    Heat is absorbed by the gas during the path $B \to C \to D$
  • C
    Work done during the path $A \to B \to C$ is zero
  • D
    Positive work is done by the gas in the cycle $ABCDA$

Explore More

Similar Questions

In the given $PV$ diagram,a system goes from state $P$ to state $Q$ along two different paths. Along path $1$,the system is given $1000 \ J$ of heat. The work done by the system along path $1$ is $100 \ J$ more than the work done along path $2$. How much heat is transferred along path $2$ (in $J$)?

Difficult
View Solution

One mole of a monatomic ideal gas undergoes the process $A \rightarrow B$ in the given $p-V$ diagram. The specific heat capacity in the process is:

$A$ thermodynamic system is taken from an original state to an intermediate state by the linear process shown in the figure. Its volume is then reduced to the original value from $E$ to $F$ by an isobaric process. Calculate the total work done (in $J$) by the gas from $D$ to $E$ to $F$.

Four curves $A, B, C$ and $D$ are drawn in the adjoining figure for a given amount of an ideal gas. The curves which represent adiabatic and isothermal expansions, respectively, are

An ideal gas is taken through the cycle $A \to B \to C \to A,$ as shown in the figure. What is the change in internal energy in $J$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo