The figure shows two semicircular loops of ra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic field at the centre of a semicircular arc of radius $R$ carrying current $I$ is given by $B = \frac{\mu_0 I}{4R}$.In the given figure

Vedclass · Accepted Answer

$\frac{\mu_0 I}{4}\left(\frac{1}{R_1}+\frac{1}{R_2}\right)$

Vedclass · Answer

(A) The magnetic field at the centre of a semicircular arc of radius $R$ carrying current $I$ is given by $B = \frac{\mu_0 I}{4R}$.In the given figure,the currents in the two semicircular arcs flow in the same sense (clockwise) relative to the centre $O$.Therefore,the magnetic fields produced by both arcs at the centre $O$ are in the same direction (into the plane of the paper).The total magnetic field at the centre $O$ is the sum of the individual magnetic fields:$B_{	ext{net}} = B_1 + B_2$$B_{	ext{net}} = \frac{\mu_0 I}{4R_1} + \frac{\mu_0 I}{4R_2}$$B_{	ext{net}} = \frac{\mu_0 I}{4} \left( \frac{1}{R_1} + \frac{1}{R_2} ight)$

Column $A$	Column $B$
$A) \frac{B}{4}$	$i) (0, 0)$
$B) \frac{B}{2}$	$ii) (a, 0)$
$C) \frac{2B}{3}$	$iii) (2a, 0)$
$D) 2B$	$iv) (3a, 0)$

The figure shows two semicircular loops of radii $R_1$ and $R_2$ carrying current $I$. The magnetic field at the common centre '$O$' is

Similar Questions

In a hydrogen atom, an electron is revolving in an orbit of radius $0.53 \, \text{\AA}$ with $6.6 \times 10^{15} \, \text{rotations/second}$. The magnetic field produced at the centre of the orbit is ....... $Wb/m^2$.

$A$ conducting wire carrying current $I$ is arranged as shown in the figure. Find the magnetic field at point $O$.

The magnetic field on the axis of a circular loop of radius $R = 100\,cm$ carrying current $I = \sqrt{2}\,A$,at a point $x = 1\,m$ away from the centre of the loop is given by:

Two insulated circular loops $A$ and $B$ of radius '$a$' carry a current of '$I$' in the directions as shown in the figure. The magnitude of the magnetic induction at the centre $O$ will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module