The final product formed when ethyl bromide i | vedclass

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(A) When ethyl bromide $(CH_3CH_2Br)$ is treated with alcoholic $KOH$,it undergoes a dehydrohalogenation reaction.This is an elimination reaction wher

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Ethylene

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(A) When ethyl bromide $(CH_3CH_2Br)$ is treated with alcoholic $KOH$,it undergoes a dehydrohalogenation reaction.This is an elimination reaction where a hydrogen atom from the $\beta$-carbon and the bromine atom from the $\alpha$-carbon are removed.The reaction is: $CH_3-CH_2-Br + KOH (	ext{alc.}) 	o CH_2=CH_2 + KBr + H_2O$.The final product formed is ethylene $(CH_2=CH_2)$.

The final product formed when ethyl bromide is treated with excess of alcoholic $KOH$ is

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