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Question

(D) In the Calvin cycle,the primary carboxylation step involves the enzyme $RuBisCO$,which catalyzes the reaction of $CO_2$ with Ribulose $1, 5$-bisph

Vedclass · Accepted Answer

$3$-phosphoglyceric acid ($3$-$PGA$)

Vedclass · Answer

(D) In the Calvin cycle,the primary carboxylation step involves the enzyme $RuBisCO$,which catalyzes the reaction of $CO_2$ with Ribulose $1, 5$-bisphosphate $(RuBP)$.This reaction produces an unstable $6$-carbon intermediate compound.This unstable compound immediately undergoes hydrolysis to form two molecules of $3$-phosphoglyceric acid ($3$-$PGA$).Therefore,$3$-$PGA$ is the first stable intermediate product of the Calvin cycle.

The first stable intermediate product formed during the Calvin cycle of photosynthesis is:

Similar Questions

How many turns of the Calvin cycle are required to form one hexose molecule?

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Why is the $RuBisCo$ enzyme more appropriately called $RuBP$ Carboxylase-Oxygenase and what important role does it play in photosynthesis?

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