The first ionization energy of boron is less | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of $Be$ $(Z=4)$ is $1s^2 2s^2$,which is a fully filled $s$-orbital.The electronic configuration of $B$ $(Z=5)$ is $1s

Vedclass · Accepted Answer

Boron has only one electron in $p$-sub-shell

Vedclass · Answer

(C) The electronic configuration of $Be$ $(Z=4)$ is $1s^2 2s^2$,which is a fully filled $s$-orbital.The electronic configuration of $B$ $(Z=5)$ is $1s^2 2s^2 2p^1$.Removing an electron from $Be$ requires breaking a stable,fully filled $2s$ subshell,which requires more energy.In contrast,the electron in $B$ is removed from the $2p$ subshell,which is easier to remove as it is shielded by the $2s$ electrons and is at a slightly higher energy level.

$I.P.$ \text{ Trend}	Reason
$A$. $N > O$	Half-filled configuration
$B$. $Zr < Hf$	Lanthanide contraction
$C$. $Na > K$	$Z_{eff}$
$D$. $Al < Ga$	Transition contraction

The first ionization energy of boron is less than that of beryllium because

Similar Questions

Which of the following represents the correct order of ionization enthalpy?
$(i) Be^{+} > Be$ $(ii) Be > Be^{+}$ $(iii) C > Be$ $(iv) B > Be$

Correct increasing order of first ionisation potential is

The correct order of second ionisation potentials $(IP)$ of $Ca$,$Ba$ and $K$ is

Identify the incorrect match regarding Ionization Potential $(I.P.)$ trends:

$I.P.$ \text{ Trend} Reason

$A$. $N > O$ Half-filled configuration

$B$. $Zr < Hf$ Lanthanide contraction

$C$. $Na > K$ $Z_{eff}$

$D$. $Al < Ga$ Transition contraction

The atomic number of the element from the following with the lowest $1^{st}$ ionisation enthalpy is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module