The first term of an A.P. is 2 and the common | vedclass

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(A) Given: First term $a = 2$,common difference $d = 4$,and number of terms $n = 40$.The formula for the sum of the first $n$ terms of an $A.P.$ is $S

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$3200$

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(A) Given: First term $a = 2$,common difference $d = 4$,and number of terms $n = 40$.The formula for the sum of the first $n$ terms of an $A.P.$ is $S_n = \frac{n}{2}[2a + (n - 1)d]$.Substituting the values into the formula:$S_{40} = \frac{40}{2}[2(2) + (40 - 1)4]$$S_{40} = 20[4 + 39 	imes 4]$$S_{40} = 20[4 + 156]$$S_{40} = 20[160]$$S_{40} = 3200$.Therefore,the sum of the first $40$ terms is $3200$.

The first term of an $A.P.$ is $2$ and the common difference is $4$. The sum of its $40$ terms will be:

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