The following compound can exhibit:

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(B) The given compound is $(CH_3)_2C=CH-CH(CH_3)-COOH$.$1$. Geometrical isomerism: The double bond is $(CH_3)_2C=CH-$. Since one of the carbons of the

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Optical isomerism

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(B) The given compound is $(CH_3)_2C=CH-CH(CH_3)-COOH$.$1$. Geometrical isomerism: The double bond is $(CH_3)_2C=CH-$. Since one of the carbons of the double bond (the left one) is attached to two identical groups (two $CH_3$ groups),it cannot exhibit geometrical isomerism.$2$. Optical isomerism: The molecule contains a chiral carbon atom at the $CH(CH_3)$ position (the carbon attached to $H$,$CH_3$,$COOH$,and the $-CH=C(CH_3)_2$ group). Since all four groups attached to this carbon are different,it is a chiral center.Therefore,the compound exhibits optical isomerism.

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