The following equilibrium constants are given | vedclass

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Question

(A) Given reactions:$(i) N_2 + 3 H_2 \rightleftharpoons 2 NH_3 ; k_1$$(ii) N_2 + O_2 \rightleftharpoons 2 NO ; k_2$$(iii) H_2 + 1/2 O_2 \rightleftharp

Vedclass · Accepted Answer

$\frac{k_2^{1/2} k_3^{3/2}}{k_1^{1/2}}$

Vedclass · Answer

(A) Given reactions:$(i) N_2 + 3 H_2 ightleftharpoons 2 NH_3 ; k_1$$(ii) N_2 + O_2 ightleftharpoons 2 NO ; k_2$$(iii) H_2 + 1/2 O_2 ightleftharpoons H_2 O ; k_3$Target reaction: $NH_3 + 5/4 O_2 ightleftharpoons NO + 3/2 H_2 O$To obtain the target reaction,we perform the following operations:$1/2 	imes (ii) + 3/2 	imes (iii) - 1/2 	imes (i)$$1/2 (N_2 + O_2 ightleftharpoons 2 NO) \Rightarrow 1/2 N_2 + 1/2 O_2 ightleftharpoons NO$ $(k_2^{1/2})$$3/2 (H_2 + 1/2 O_2 ightleftharpoons H_2 O) \Rightarrow 3/2 H_2 + 3/4 O_2 ightleftharpoons 3/2 H_2 O$ $(k_3^{3/2})$$-1/2 (N_2 + 3 H_2 ightleftharpoons 2 NH_3) \Rightarrow NH_3 ightleftharpoons 1/2 N_2 + 3/2 H_2$ $(k_1^{-1/2})$Adding these gives: $NH_3 + 5/4 O_2 ightleftharpoons NO + 3/2 H_2 O$The equilibrium constant $K = \frac{k_2^{1/2} 	imes k_3^{3/2}}{k_1^{1/2}}$.

Similar Questions

For the reaction $x \rightleftharpoons y$,which of the following factors will affect the value of $[\text{Product}] / [\text{Reactant}]^{-1}$ at equilibrium?

What is $K_{c}$ for the following equilibrium when the equilibrium concentration of each substance is: $[SO_{2}] = 0.60 \, M, [O_{2}] = 0.82 \, M$ and $[SO_{3}] = 1.90 \, M?$
$2SO_{2(g)} + O_{2(g)} \longleftrightarrow 2SO_{3(g)}$

In the figure shown below,reactant $A$ (represented by square) is in equilibrium with product $B$ (represented by circle). The equilibrium constant is:

The suitable expression for the equilibrium constant of the reaction $2NO_{(g)} + Cl_{2(g)} \rightleftharpoons 2NOCl_{(g)}$ is

For the reactions:
$A \rightleftharpoons B$ $K_C = 2$
$B \rightleftharpoons C$ $K_C = 3$
$C \rightleftharpoons D + E$ $K_C = 5$
$K_C$ for the reaction $A \rightleftharpoons D + E$ is:

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