(A) In the given displacement-time graph,the position $x$ of the object remains constant as time $t$ increases.Since the slope of the displacement-tim

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The graph shows an object at rest.

(A) In the given displacement-time graph,the position $x$ of the object remains constant as time $t$ increases.Since the slope of the displacement-time graph represents velocity $(v = dx/dt)$,and the slope of a horizontal line is zero,the velocity of the object is zero.Therefore,the graph indicates that the object is at rest.

Class 11 Physics Motion in a Straight Line Instantaneous Velocity and Speed and Velocity-time Graph

Medium

The following figure shows the variation of displacement $x$ with time $t$ for a particular object. Identify the correct interpretation of the graph.

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A
The graph shows an object at rest.
B
The graph shows an object moving with uniform velocity in the positive $x$ direction.
C
The graph shows an object moving with uniform velocity in the negative $x$ direction.
D
The graph shows an object moving with non-uniform acceleration.

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Motion in a Straight Line

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Instantaneous Velocity and Speed and Velocity-time Graph

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The velocity-displacement $(v-s)$ graph shows the motion of a particle moving in a straight line. The velocity-displacement graph is a circle of radius $2 \ m$ and the center is at $(2, 0) \ m$. The value of acceleration for this particle at a point $(2-\sqrt{2}, \sqrt{2}) \ m$ will be $ms^{-2}$.

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The velocity of a particle moving on the $x$-axis is given by $v = x^2 + x$,where $v$ is in $m/s$ and $x$ is in $m$. Find its acceleration in $m/s^2$ when passing through the point $x = 2 \ m$.

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Which of the following position-time $(s-t)$ graphs represents uniform acceleration?

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The position-time $(x-t)$ graph for positive acceleration is

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The velocity-displacement graph of a particle moving in a straight line is as shown in the figure.

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The following figure shows the variation of displacement $x$ with time $t$ for a particular object. Identify the correct interpretation of the graph.

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The velocity-displacement $(v-s)$ graph shows the motion of a particle moving in a straight line. The velocity-displacement graph is a circle of radius $2 \ m$ and the center is at $(2, 0) \ m$. The value of acceleration for this particle at a point $(2-\sqrt{2}, \sqrt{2}) \ m$ will be $ms^{-2}$.

The velocity of a particle moving on the $x$-axis is given by $v = x^2 + x$,where $v$ is in $m/s$ and $x$ is in $m$. Find its acceleration in $m/s^2$ when passing through the point $x = 2 \ m$.

Which of the following position-time $(s-t)$ graphs represents uniform acceleration?

The position-time $(x-t)$ graph for positive acceleration is

The velocity-displacement graph of a particle moving in a straight line is as shown in the figure.

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