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(B) The formula for surface tension is $T = \frac{rhg}{2} 	imes 10^3$. Here,$r = D/2$,so $\frac{\Delta r}{r} = \frac{\Delta D}{D}$.The relative error

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

(B) The formula for surface tension is $T = \frac{rhg}{2} 	imes 10^3$. Here,$r = D/2$,so $\frac{\Delta r}{r} = \frac{\Delta D}{D}$.The relative error in $T$ is given by $\frac{\Delta T}{T} = \frac{\Delta r}{r} + \frac{\Delta h}{h}$.Assuming the least count for both $D$ and $h$ is $0.01 	imes 10^{-2} \ m$ (based on the precision of the given values):$\frac{\Delta r}{r} = \frac{0.01 	imes 10^{-2}}{1.25 	imes 10^{-2}} = \frac{0.01}{1.25} = 0.008$.$\frac{\Delta h}{h} = \frac{0.01 	imes 10^{-2}}{1.45 	imes 10^{-2}} = \frac{0.01}{1.45} \approx 0.00689$.Percentage error $= \left( \frac{\Delta T}{T} ight) 	imes 100 = (0.008 + 0.00689) 	imes 100 = 0.01489 	imes 100 = 1.489\%$.Rounding to the nearest value,we get $1.5\%$.

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