The following plots show the variation of vel | vedclass

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(C) When a ball is thrown vertically upward with an initial velocity $u$, its velocity at any time $t$ is given by the equation of motion: $v = u - gt

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Plot $(C)$

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(C) When a ball is thrown vertically upward with an initial velocity $u$, its velocity at any time $t$ is given by the equation of motion: $v = u - gt$, where $g$ is the acceleration due to gravity.$1$. Initially, the velocity is positive $(v = u)$.$2$. As the ball rises, the velocity decreases linearly with time because of the constant downward acceleration $g$.$3$. At the maximum height, the velocity becomes zero.$4$. After reaching the maximum height, the ball starts falling downward. During this phase, the velocity becomes negative (as it is directed opposite to the initial upward direction) and its magnitude increases linearly with time.This linear relationship $v = u - gt$ represents a straight line with a negative slope $(-g)$. Plot $(C)$ correctly depicts this variation, starting from a positive initial velocity, crossing the time axis (where $v = 0$), and continuing into the negative velocity region.

The following plots show the variation of velocity $(v)$ with time $(t)$ for a ball thrown vertically upward and falling back. Which of the following plots is correct?

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