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(B) Step $1$: Subtract $1$ from the last digit of each number.$972 \rightarrow 97(2-1) = 971$$526 \rightarrow 52(6-1) = 525$$487 \rightarrow 48(7-1) =

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(B) Step $1$: Subtract $1$ from the last digit of each number.$972 \rightarrow 97(2-1) = 971$$526 \rightarrow 52(6-1) = 525$$487 \rightarrow 48(7-1) = 486$$359 \rightarrow 35(9-1) = 358$$251 \rightarrow 25(1-1) = 250$Step $2$: Calculate the sum of the digits for each resulting number.Sum of digits of $971 = 9 + 7 + 1 = 17$Sum of digits of $525 = 5 + 2 + 5 = 12$Sum of digits of $486 = 4 + 8 + 6 = 18$Sum of digits of $358 = 3 + 5 + 8 = 16$Sum of digits of $250 = 2 + 5 + 0 = 7$Step $3$: Identify which sums are prime numbers.The sums are $17, 12, 18, 16, 7$.Among these,$17$ and $7$ are prime numbers.Therefore,there are $2$ such numbers.

The following questions are based on the five three-digit numbers given below:
$972, 526, 487, 359, 251$
If $1$ is subtracted from the last digit of each of the above numbers,the sum of the digits of how many of them are prime numbers?

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The following questions are based on the five three-digit numbers given below:$972, 526, 487, 359, 251$If $1$ is subtracted from the last digit of each of the above numbers,the sum of the digits of how many of them are prime numbers?