The following reaction sequence is given:
Phenol $\xrightarrow{NaOH} X$ $\xrightarrow[(ii) H^+]{(i) CO_2} Y$ $\xrightarrow{(CH_3CO)_2O/H^+} Z + CH_3COOH$
The correct statements about $Z$ from the following are:
$I$. It is $o$-hydroxybenzoic acid.
$II$. It is a non-narcotic analgesic.
$III$. It acts as antipyretic.
$IV$. It acts as antihistamine.

  • A
    $II$ and $III$
  • B
    $I$ and $IV$
  • C
    $II$ and $IV$
  • D
    $I$ and $II$

Explore More

Similar Questions

Phenol can be distinguished from ethanol by the reagent

Phenol on treatment with dil. $HNO_3$ gives two products $P$ and $Q$. $P$ is steam volatile but $Q$ is not. $P$ and $Q$ are,respectively:

The following reaction is known as:
$Phenol \xrightarrow[H^{+}]{CHCl_3 / NaOH} \text{Salicylaldehyde}$

In the reaction of phenol with $NaOH(aq)/Br_2$,the intermediate$(s)$ is(are):

Which among the following is a dihydric phenol?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo