The following sequence of reaction on A gives | vedclass

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(C) The starting material is methyl $2-(2-amino-2-oxoethyl)benzoate$. Step $1$: The reaction with $Br_2/NaOH$ is a Hoffmann bromamide degradation,whic

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(C) The starting material is methyl $2-(2-amino-2-oxoethyl)benzoate$. Step $1$: The reaction with $Br_2/NaOH$ is a Hoffmann bromamide degradation,which converts the $-CONH_2$ group into a $-NH_2$ group,yielding methyl $2-(aminomethyl)benzoate$. Step $2$: Upon heating,the amino group undergoes an intramolecular nucleophilic attack on the ester group $(-COOCH_3)$,resulting in the elimination of methanol $(CH_3OH)$ and the formation of the cyclic amide,$isoindolin-1-one$.

The following sequence of reaction on $A$ gives:

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