The following solutions were prepared by dissolving $10 \ g$ of glucose $(C_{6}H_{12}O_{6})$ in $250 \ mL$ of water $(P_{1})$,$10 \ g$ of urea $(CH_{4}N_{2}O)$ in $250 \ mL$ of water $(P_{2})$,and $10 \ g$ of sucrose $(C_{12}H_{22}O_{11})$ in $250 \ mL$ of water $(P_{3})$. The right option for the decreasing order of osmotic pressure of these solutions is:

  • A
    $P_{2} > P_{1} > P_{3}$
  • B
    $P_{1} > P_{2} > P_{3}$
  • C
    $P_{2} > P_{3} > P_{1}$
  • D
    $P_{3} > P_{1} > P_{2}$

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At $27^{\circ} C$,the osmotic pressure of a solution containing $4 \ g$ of a non-electrolyte solute in $1.0 \ L$ of solution is $0.4 \ bar$. The molar mass of the solute in $g \ mol^{-1}$ is :
$(R=0.083 \ L \ bar \ K^{-1} \ mol^{-1})$

At a constant temperature,the osmotic pressures of a $1.5 \ M \ NH_4NO_3$ aqueous solution and an $x \ M \ Al_2(SO_4)_3$ aqueous solution are approximately equal. Find the value of $x$. (Assume $100 \%$ dissociation of the solute in the solution.)

$A$ $5.25\%$ solution of a substance is isotonic with a $1.5\%$ solution of urea (molar mass $= 60\ g\ mol^{-1}$) in the same solvent. If the densities of both the solutions are assumed to be equal to $1.0\ g\ cm^{-3},$ the molar mass of the substance will be .............. $g\ mol^{-1}$.

$A$ $0.002 \, M$ solution of $NaCl$ having a degree of dissociation of $90 \%$ at $27 \, ^{\circ}C$ has an osmotic pressure equal to:

To have an osmotic pressure equal to a solution containing $9.2 \ g$ of glucose per liter,how many grams of glucose must be dissolved in $0.5 \ L$ of solution?

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