The force on a charge situated on the axis of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The electric field $E$ on the axis of a dipole at a distance $r$ is given by $E = \frac{2kp}{r^3}$,where $k$ is Coulomb's constant and $p$ is the

Vedclass · Accepted Answer

$\frac{F}{8}$

Vedclass · Answer

(D) The electric field $E$ on the axis of a dipole at a distance $r$ is given by $E = \frac{2kp}{r^3}$,where $k$ is Coulomb's constant and $p$ is the dipole moment.Since the force on a charge $q$ is $F = qE$,we have $F = q \left( \frac{2kp}{r^3} \right) \propto \frac{1}{r^3}$.If the distance is doubled,the new distance $r' = 2r$.The new force $F'$ will be $F' = q \left( \frac{2kp}{(2r)^3} \right) = q \left( \frac{2kp}{8r^3} \right) = \frac{1}{8} F$.Therefore,the new force is $\frac{F}{8}$.

The force on a charge situated on the axis of a dipole is $F$. If the charge is shifted to double the distance,the new force will be

Similar Questions

$A$ and $B$ are two points on the axis and the perpendicular bisector respectively of an electric dipole. $A$ and $B$ are far away from the dipole and at equal distance from it. The electric fields at $A$ and $B$ are $\vec{E}_A$ and $\vec{E}_B$.

Mention the direction of the electric dipole moment. Write the $SI$ unit of the electric dipole moment.

An electric dipole consists of two opposite charges each of magnitude $1 \,\mu C$ separated by a distance of $2 \,cm$. The dipole is placed in an external field of $10^5 \,N/C$. The maximum torque on the dipole is ......... $Nm$.

When a test charge is brought in from infinity along the perpendicular bisector of an electric dipole,the work done is ..........

If a dipole of dipole moment $\vec{p}$ is placed in a uniform electric field $\vec{E}$,then the torque acting on it is given by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module