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(D) The electric field $E$ on the axis of a dipole at a distance $r$ is given by $E = \frac{2Kp}{r^3}$,where $K$ is Coulomb's constant and $p$ is the

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$F/8$

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(D) The electric field $E$ on the axis of a dipole at a distance $r$ is given by $E = \frac{2Kp}{r^3}$,where $K$ is Coulomb's constant and $p$ is the dipole moment.The force $F$ on a charge $q$ is given by $F = qE = q \left( \frac{2Kp}{r^3} \right) = \frac{2Kpq}{r^3}$.From this expression,we see that $F \propto \frac{1}{r^3}$.If the distance is doubled,i.e.,$r' = 2r$,the new force $F'$ will be:$F' = \frac{2Kpq}{(2r)^3} = \frac{2Kpq}{8r^3} = \frac{1}{8} \left( \frac{2Kpq}{r^3} \right) = \frac{F}{8}$.

The force on a charge situated on the axis of a dipole is $F$. If the charge is shifted to double the distance,the new force will be

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