The force required to move a body up a rough | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $m$ be the mass of the body,$	heta$ be the angle of inclination,and $\mu$ be the coefficient of friction.The force required to move the body

Vedclass · Accepted Answer

$\frac{1}{\sqrt{3}}$

Vedclass · Answer

(C) Let $m$ be the mass of the body,$	heta$ be the angle of inclination,and $\mu$ be the coefficient of friction.The force required to move the body up the inclined plane is $F_{up} = mg \sin 	heta + \mu mg \cos 	heta$.The force required to prevent the body from sliding down the inclined plane is $F_{down} = mg \sin 	heta - \mu mg \cos 	heta$.According to the problem,$F_{up} = 2 F_{down}$.Substituting the expressions,we get:$mg \sin 	heta + \mu mg \cos 	heta = 2(mg \sin 	heta - \mu mg \cos 	heta)$Dividing both sides by $mg$:$\sin 	heta + \mu \cos 	heta = 2 \sin 	heta - 2 \mu \cos 	heta$Rearranging the terms to solve for $\mu$:$3 \mu \cos 	heta = \sin 	heta$$\mu = \frac{1}{3} 	an 	heta$Given $	heta = 60^{\circ}$,we have:$\mu = \frac{1}{3} 	an 60^{\circ} = \frac{1}{3} 	imes \sqrt{3} = \frac{1}{\sqrt{3}}$.

The force required to move a body up a rough inclined plane is double the force required to prevent the body from sliding down the plane. If the angle of inclination of the plane is $60^{\circ}$,then the coefficient of friction is

Similar Questions

The $emf$ (in $V$) of a Daniell cell containing $0.1 \ M$ $ZnSO_4$ and $0.01 \ M$ $CuSO_4$ solutions at their respective electrodes is
$(E_{Cu^{2+} / Cu}^{\circ} = +0.34 \ V; E_{Zn^{2+} / Zn}^{\circ} = -0.76 \ V)$

If the extremities of a diagonal of a square are $(1, -2, 3)$ and $(2, -3, 5)$, then the length of its side is

In which disease does fluid accumulate in the alveoli and bronchioles?

The equation of a plane containing the line of intersection of the planes $2x - y - 4 = 0$ and $y + 2z - 4 = 0$ and passing through the point $(1, 1, 0)$ is:

The angle between the tangents drawn from the point $(1,4)$ to the parabola $y^2=4x$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module