The formal oxidation numbers of $Cr$ and $Cl$ in the ions $Cr_2O_7^{2-}$ and $ClO_3^{-}$ respectively are
- A$+6$ and $+5$
- B$+7$ and $+5$
- C$+6$ and $+7$
- D$+8$ and $+7$
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Similar Questions
The oxidation number of sulphur in $S_2O_3^{2-}$ is:
Easy
View SolutionMatch the following Column-$I$ to Column-$II$ based on the oxidation state of the underlined nitrogen atom:
Column-$I$ Column-$II$ $A$. $\underline{N}H_4 Cl$ $P$. $+1$ $B$. $H\underline{N}O_3$ $Q$. $+5$ $C$. $\underline{N}_2 O$ $R$. $-3$ $D$. $\underline{N}H_2 OH$ $S$. $-1$
| Column-$I$ | Column-$II$ |
|---|---|
| $A$. $\underline{N}H_4 Cl$ | $P$. $+1$ |
| $B$. $H\underline{N}O_3$ | $Q$. $+5$ |
| $C$. $\underline{N}_2 O$ | $R$. $-3$ |
| $D$. $\underline{N}H_2 OH$ | $S$. $-1$ |
Easy
View SolutionThe correct order of $N$ compounds in their decreasing order of oxidation states is:
MediumNEET 2018
View SolutionThe oxidation number of carbon in $CH_2O$ is
Oxidation state of oxygen in $F_2O$ is
Medium
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