The formula of a metal oxide is M_{0.96} O_1. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $x$ be the number of $M^{3+}$ ions and $y$ be the number of $M^{2+}$ ions.Total number of metal ions is $x + y = 0.96$.Therefore, $y = 0.96 -

Vedclass · Accepted Answer

$0.083, 0.916$

Vedclass · Answer

(A) Let $x$ be the number of $M^{3+}$ ions and $y$ be the number of $M^{2+}$ ions.Total number of metal ions is $x + y = 0.96$.Therefore, $y = 0.96 - x$.Since the oxide is electrically neutral, the total positive charge must equal the total negative charge ($-2$ for $O^{2-}$).$3x + 2y = 2$.Substituting $y = 0.96 - x$ into the equation:$3x + 2(0.96 - x) = 2$.$3x + 1.92 - 2x = 2$.$x = 0.08$.Thus, $y = 0.96 - 0.08 = 0.88$.The fraction of $M^{3+} = \frac{0.08}{0.96} = 0.083$.The fraction of $M^{2+} = \frac{0.88}{0.96} = 0.917$.

The formula of a metal oxide is $M_{0.96} O_1$. The fractions of metal that exist as $M^{3+}$ and $M^{2+}$ ions in that oxide are respectively

Similar Questions

If molten $NaCl$ contains $SrCl_2$ as impurity,crystallization can generate

Explain the defects arising due to anionic vacancies and due to the presence of extra cations in the interstitial sites.

The formula of nickel oxide is $Ni_{0.98}O_{1.00}$. What is the approximate percentage of $Ni^{2+}$ in it?

Iron crystallizes in $FCC$ with an edge length of $400 \ pm$. If it contains $0.1 \%$ Schottky defects, calculate its approximate density $[AW \text{ of } Fe = 56 \ g/mol]$. (in $g/cm^3$)

Explain the following term with a suitable example:
$(ii)$ Frenkel defect

Vedclass Test Series

Exam Paper Generator

Online Exam Module