The four quantum numbers for the electron in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electronic configuration of potassium $(Z=19)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^1$.The outermost electron enters the $4s$ orbital.For the

Vedclass · Accepted Answer

$n=4, l=0, m=0, s=+\frac{1}{2}$

Vedclass · Answer

(B) The electronic configuration of potassium $(Z=19)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^1$.The outermost electron enters the $4s$ orbital.For the $4s$ orbital,the principal quantum number $n=4$.Since it is an $s$-orbital,the azimuthal quantum number $l=0$.Consequently,the magnetic quantum number $m=0$.The spin quantum number $s$ can be $+\frac{1}{2}$ or $-\frac{1}{2}$.Comparing this with the given options,option $B$ is correct.

The four quantum numbers for the electron in the outermost orbital of potassium (atomic number $19$) are:

Similar Questions

What is the difference between the terms orbit and orbital?

The maximum number of electrons accommodated in $5f$ orbitals are

Write down about the electron spin quantum number $(s)$.

Which one of the following configurations represents a noble gas?

From which principal quantum number $(n)$ do the $s, p, d,$ and $f$ orbitals start? Describe them.

Vedclass Test Series

Exam Paper Generator

Online Exam Module