The four quantum numbers for the valence shel | vedclass

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Question

(B) The electronic configuration of Sodium $(Z=11)$ is $1s^2, 2s^2, 2p^6, 3s^1$. The valence shell electron is in the $3s$ orbital. For the $3s$ orbit

Vedclass · Accepted Answer

$n=3, \ell=0, m=0, s=+\frac{1}{2}$

Vedclass · Answer

(B) The electronic configuration of Sodium $(Z=11)$ is $1s^2, 2s^2, 2p^6, 3s^1$. The valence shell electron is in the $3s$ orbital. For the $3s$ orbital,the principal quantum number $n = 3$. For an $s$-orbital,the azimuthal quantum number $\ell = 0$. Since $\ell = 0$,the magnetic quantum number $m = 0$. The spin quantum number $s$ for the first electron in an orbital is typically taken as $+\frac{1}{2}$.

The four quantum numbers for the valence shell electron of Sodium $(Z=11)$ are:

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