The freezing points of equimolar solutions of | vedclass

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(A) Depression in freezing point $(\Delta T_f)$ is a colligative property,which is directly proportional to the van't Hoff factor $(i)$ for equimo

Vedclass · Accepted Answer

$AlCl_3 < KNO_3 < 	ext{Glucose}$

Vedclass · Answer

(A) Depression in freezing point $(\Delta T_f)$ is a colligative property,which is directly proportional to the van't Hoff factor $(i)$ for equimolar solutions: $\Delta T_f = i 	imes K_f 	imes m$.
For the given solutes:
$i (	ext{Glucose}) = 1$ (non-electrolyte)
$i (KNO_3) = 2$ $(K^{+} + NO_3^{-})$
$i (AlCl_3) = 4$ $(Al^{3+} + 3Cl^{-})$
Since $\Delta T_f \propto i$,the order of depression in freezing point is: $	ext{Glucose} < KNO_3 < AlCl_3$.
Freezing point $(T_f)$ is related to depression as $T_f = T_f^{\circ} - \Delta T_f$.
Therefore,a higher depression leads to a lower freezing point.
The correct order of freezing points is: $AlCl_3 < KNO_3 < 	ext{Glucose}$.

The freezing points of equimolar solutions of glucose,$KNO_3$ and $AlCl_3$ are in the order of:

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