The frequency for which a 5 mu F capacitor ha | vedclass

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Question

(C) The capacitive reactance $X_c$ is given by the formula: $X_c = \frac{1}{2 \pi f C}$.Given values are $X_c = \frac{1}{1000} \Omega = 10^{-3} \Omega

Vedclass · Accepted Answer

$\frac{100}{\pi} 	ext{ MHz}$

Vedclass · Answer

(C) The capacitive reactance $X_c$ is given by the formula: $X_c = \frac{1}{2 \pi f C}$.Given values are $X_c = \frac{1}{1000} \Omega = 10^{-3} \Omega$ and $C = 5 \mu F = 5 	imes 10^{-6} 	ext{ F}$.Substituting these values into the formula:$10^{-3} = \frac{1}{2 \pi f (5 	imes 10^{-6})}$$10^{-3} = \frac{1}{10 \pi f 	imes 10^{-6}}$$10^{-3} = \frac{1}{\pi f 	imes 10^{-5}}$Rearranging for frequency $f$:$f = \frac{1}{10^{-3} 	imes \pi 	imes 10^{-5}} = \frac{1}{\pi 	imes 10^{-8}} = \frac{10^8}{\pi} 	ext{ Hz}$.Since $1 	ext{ MHz} = 10^6 	ext{ Hz}$,we have $f = \frac{100 	imes 10^6}{\pi} 	ext{ Hz} = \frac{100}{\pi} 	ext{ MHz}$.

The frequency for which a $5 \mu F$ capacitor has a reactance of $\frac{1}{1000} \Omega$ is given by

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